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Old May 12, 2011 | 11:29 AM
  #11206  
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Originally Posted by exiled
Your right I just don't get it. So can please use a picture to explain it for me. Like useing some kind of math? I'm not arguing I want understand this. I guess I'm the only one in this thread trying to learn something. Yall keep saying your not making peak tq unless your at WOT. Aight I left that alone. I hope everyone here agreed both engines make different numbers at peak. Aight well your goimg to make a % of that. If you didn't how it continue to move. The same percent of different numbers is going to be different.
Why do you have to be at WOT reach advertised numbers? I can't get my head around this. I cant spell what I'm trying to say and its mot even close. What is the difference of 2200 rpm at 10 mpg or 18 mpg. What is the reasoning that the throttle haveing to be maxed to get peak numbers?
This may not be the best explanation, but I'll take a stab at it. And hopefully I won't say anything completly wrong. I will explain with a gas engine. A diesel would be different in how its throttled, but with similar results.

Obviously, a truck on level ground requires less power to move at a given speed than the same truck on a 10% grade, yet it can maintain the same speed in the same gear at both times (unloaded, in this case). The same engine at the same rpm has to be able to produce different levels of power. For a gas engine, this is done with the throttle. A gas engine needs to run at an approximately stoichiometric ratio of mass of air to mass of fuel. For every ~14.7 lbs of air into the engine, you need ~1 lb of fuel.

You control the amount of air going into the engine with the accelerator, which opens and closes the throttle plate. The engine then, by computer controlled injectors, adjusts the fuel to match the air flow. If the throttle is not fully open, then engine cannot pull in enough air to "fill" the cylinders. Air, being a gas, will naturally fill the cylinders, just at a lower pressure. The mass of air that the engine could contain is less than it could hold at atmospheric pressure. This is known as the volumetric efficiency of the engine, and, for a given engine, it varies with both throttle opening and engine rpm. Under part throttle cruise, volumetric efficiency will be much less than 100% (I think my car is in the mid 30's), while at WOT it can exceed 100%.

Since the mass of air flowing through the engine varies, so does the amount of fuel burned. And with less fuel burned, less power is generated.

Clear as mud?
 
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Old May 12, 2011 | 11:45 AM
  #11207  
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Originally Posted by '89F2urd
as far as the "2200 at 10 mpg vs 2200 at 18mpg" - - - when you mash the pedal demanding more fuel, your mileage obviously decreases. just cuz youre at a particular rpm doesnt mean you will get a particular mpg. . .there are more variables than that. the more power you wanna feel at a particular rpm, the harder you push the pedal, and in turn the more fuel you are burning. cuz more fuel + air = more power, at any rpm.
I was just describing a fuel load. My theroy at this point is. A engine is rated by a x output at a y rpm. Period. That's the max the engine can produce no matter how much fuel you give or rpm. Right? Youbuild the output until peak at a give rpm then after that your just building speed. I do not understand whst the fuelload has to do with it as long as its enough to get you to that peak.
So say I finally understand. Aight then just as you said only using a percentage of peak output. I'll buy that but, same percentage or close at different peak outputs = different outputs. Yes/ no?
So I'm am to take it that if where to put 2 same SDs on a dyno w/ different engines and you add weights to the lighter engine SD and you put em on cruise at 65 mph both trucks is going to show same output numbers? I've been googling this for an hour and can't find a dyno chart like this. I've even tried finding dyno results of just running at hyway rpms w/ no luck.
 
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Old May 12, 2011 | 12:05 PM
  #11208  
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Yes if you take two different engines and place the same load on them they will show the same power at the same load conditions if all you are doing is holding that load at a constant. I doubt you will ever find a dyno curve showing this. It takes "X" amount of power to move a said load at 65 mph. It doesn't matter what the engine is, the amount of power required is the same. Where the difference lies is how much power each engine holds in reserve that can be called upon when needed whether it be pulling out to pass or climbing a hill.
 
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Old May 12, 2011 | 12:20 PM
  #11209  
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Originally Posted by exiled
I was just describing a fuel load. My theroy at this point is.A engine is rated by a x output at a y rpm. Period. That's the max the engine can produce no matter how much fuel you give or rpm. Right? Youbuild the output until peak at a give rpm then after that your just building speed. I do not understand whst the fuelload has to do with it as long as its enough to get you to that peak. if youre not throttling 100% (WOT), not fueling 100%, you will not reach the "peak numbers" youre stuck on (100% power potential of a given setup). i.e. at part throttle (as a percentage of WOT) the motor is only receiving part fuel (as a percentage of WOT) so its output is only "part power" (A PERCENTAGE OF MAX POWER RATING AT THAT PARTICULAR RPM). . .
So say I finally understand. Aight then just as you said only using a percentage of peak output. I'll buy that but, same percentage or close at different peak outputs = different outputs. Yes/ no?
So I'm am to take it that if where to put 2 same SDs on a dyno w/ different engines and you add weights to the lighter engine SD and you put em on cruise at 65 mph both trucks is going to show same output numbers? for two different vehicles to have the same output at the same speed on the same road, both have to be identical in weights/load. wont matter what motor is in it, the power needed to move a certain weight a certain speed is the same (this is why hp can be calculated by a 1/4 mile time, along with trap speed and weight). if one motor had 400 hp, and the other motor had 200 hp, and it took 200 hp to move the trucks at the same speed, then the 200 hp truck would be exerting 100% power, while the other one would be exerting 50% (i know thats a jumbled mess) on the other end of the spectrum, a honda civic driving right next to you on the highway takes much less power to move the same speed. I've been googling this for an hour and can't find a dyno chart like this. I've even tried finding dyno results of just running at hyway rpms w/ no luck. you seem to be missing the relationship between rpm, load, and power production. lets say "highway rpm" is 2500. . .2500rpm @ 50% throttle will give a power number in the range of 35-50% of what the dyno numbers claim the power is 100% throttle at 2200 rpm

ugh. . .you cant find a dyno chart for this because no1 conducts "highway load" dyno runs. 1) cuz no1 cares, and 2) the amount of research needed to accurately conduct such an experiment would not be worth the trouble. you'd have to take into account air resistance, drag, drivetrain load, tire size, gear size, grade, and much more to determine the load to place on the dyno (yikes).

you could, on the other hand, monitor your throttle position (in % of WOT), and do dyno runs that way. it would give you an idea of relationship between the skinny pedal and power production. but again, im not sure if anyone who's done this cares to post up his results on the internet. not to mention max rpm requires 100% throttle, so you'd be conducting dyno runs with considerably less rpm as a redline.
 
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Old May 12, 2011 | 12:43 PM
  #11210  
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Originally Posted by David N.

Since the mass of air flowing through the engine varies (depending on throttle position-i.e. air allowed into the engine like you said above), so does the amount of fuel burned. And with less fuel burned, less power is generated.

Clear as mud?

this here's clear as drinking water.
 
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Old May 12, 2011 | 12:46 PM
  #11211  
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Originally Posted by Super08
Yes if you take two different engines and place the same load on them they will show the same power at the same load conditions if all you are doing is holding that load at a constant. I doubt you will ever find a dyno curve showing this. It takes "X" amount of power to move a said load at 65 mph. It doesn't matter what the engine is, the amount of power required is the same. Where the difference lies is how much power each engine holds in reserve that can be called upon when needed whether it be pulling out to pass or climbing a hill.
Funny part, I still remember old car add saying that it takes 8HP to push compact car at 50 mph. YES >>>> EIGHT PONIES.
So it takes probably 30 to push Superduty at highway speeds. All excess power is for acceleration and hill climbing.
 
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Old May 12, 2011 | 01:22 PM
  #11212  
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Originally Posted by exiled
Tq and hp isn't a ploy to sell you on an engine it is actually numbers to show the work ability of the engine. That's like saying the watt rateing on a light bulb is meaningless.we all know that it does. Hp and watt just about the same thing.
You're right, HP and watt ARE the same. The HP is the number you should pay attention to, because it incorporates both torque and speed, and is the true measure of the truck's ability.

Engine torque is indeed, to some extent, a ploy. Yes, it tells you a little something about how the truck will behave under load, but the torque number alone tells you nothing about the ultimate ability of the truck. Not enough information.
 
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Old May 12, 2011 | 01:28 PM
  #11213  
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Originally Posted by PorchFarms
if a truck has 1000 hp but 100 ft lbs of torque then it can't get a heavy load moving
It certainly can, if it's got the right gears.


Originally Posted by bucci
If I'm cruising at 2000 rpm at 60 mph on flat ground and I come to a steeper grade. I apply more throtte to maintain 2000 rpm and 60 mph and the truck remains in the same gear. It does not downshift. Is the truck putting the same power to the ground in both situations?
No. When you get to the hill and add throttle, while the wheel RPM remains the same, the rear-wheel torque goes up. Power is speed times torque. The speed remained the same, but the torque went up, so you are putting more power to the ground. And, of course, your engine is producing more HP.
 
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Old May 12, 2011 | 01:41 PM
  #11214  
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An engine with 100ft/lbs of torque, and 1000HP would run at 52520 RPM. Yes, 52,520 RPM.
 
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Old May 12, 2011 | 01:42 PM
  #11215  
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Originally Posted by KelVarnson
You're right, HP and watt ARE the same. The HP is the number you should pay attention to, because it incorporates both torque and speed, and is the true measure of the truck's ability.

Engine torque is indeed, to some extent, a ploy. Yes, it tells you a little something about how the truck will behave under load, but the torque number alone tells you nothing about the ultimate ability of the truck. Not enough information.

the same thing could be said about hp (it being a ploy). . .and neither, by themselves, tells the entire story (if anything). . .

a 500 hp semi motor (somethin akin to 14-15 liters) generally has anywhere between 1500-2000 lb/ft of torque (stock. . .the amount after mods is immense[3-3500 lb/ft]). any one of us can match the 500 horse. . .and 1000 lb/ft is easily attainable with any diesel in a 3/4 ton. . .but the semi motor has the capability of towing loads that would be laughable for our trucks at 500/1000. . .or 1000/1000 for you heavily modded gassers out there lookin to have 1000 lb/ft worth of towing capability. the reason the hp is so low, is cuz the rpm is low also. yes, torque can be used as a measurement of performance. in fact, its needed in most instances to calculate hp. . .

you can guestimate, rather accurately, a motors displacement and max rpm from its hp/tq numbers. in turn, you could guestimate its "ability" to do work (basically for which application the motor would perform optimally[car,truck,drag racer,etc]). if you only have a torque value, or only have a hp value, not much can be said.
 
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Old May 12, 2011 | 01:47 PM
  #11216  
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Originally Posted by Krewat
An engine with 100ft/lbs of torque, and 1000HP would run at 52520 RPM. Yes, 52,520 RPM.
What?
 
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Old May 12, 2011 | 01:52 PM
  #11217  
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Originally Posted by plgebbia
What?
yep, what hes saying is that a theoretical 50cc motor that can capably (breath) spin to 52,525 rpm can make 1000 hp. . . .meanwhile guzzing as much fuel as his truck would at 1000 hp
 
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Old May 12, 2011 | 01:53 PM
  #11218  
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Assuming that 100ft/lbs and 1000HP happens at the same RPM.

HP=Torque*RPM/5252

So, if HP=1000, and torque=100,

1000*5252=Torque*RPM
5252000=100*RPM
52520=RPM.
 
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Old May 12, 2011 | 01:54 PM
  #11219  
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At least mine isn't wrapped in a Dodge...
 
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Old May 12, 2011 | 01:59 PM
  #11220  
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Originally Posted by Krewat
At least mine isn't wrapped in a Dodge...
you dont think im a dodge fan do you? just went for the strongest components available (none of which are dodge). . . .and yes its a shame its all wrapped in (what inevitably will be) a leaky, rusty, dodge body with an underpowered steering box.
 
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