alright guys, idk what to do now. i have heard that the lower the resistance the more power, but now people are saying the higher the resistance, the more power. i already have the 10k done, but this weekend im gunna switch it out. should i switch it out with a lower resistance or a higher one? kinda confused here.

 

the 10k mod you already have would need lower resistance for more power. The new mod is spliced inline not jumping two wires on the back of the sensor and it works more resistance equals more power.

 

thanks for explaining that Tim. I was following that thread in wonder. I guess all I knew was the old way of doing the 10k. So if ya have the jumper on your icp sensor then ya want to go lower to say a 5.6k for more power.

 

if time permits i want to do more pictures of the "old" version. i will take volt readings on the signal wire with the 5k, 10k, 15k installed the "old" way to see what effect it has on the pcm signal voltage.
As of right now i cant comment on the resistance values for the "old" mod, but if you run it the way i do it then yes, the more resistance, the more power, this is nothing new, that is the way resistance effects any electrical circuit. resistance in a circuit "uses" voltage to overcome the load of the resistor, however in a normal circuit you are not limited to 5 volts, you are limited the the maximum flow of your fuse and power source capability. for instance, your 12 volt car battery is the source, you have a 5 amp fuse proctecting your headlight circuit. the resistor on the 10k is like adding a fog light to the headlight circuit. the extra light is more resistnace in the circuit. the only difference is the light circuit will now draw more current(amps) to overcome the resistance of the fog light and return to ground. this occurs because the battery is your source and has the capabilty of 1000 amps(or whatever yours is rated), the fuse is your limiter in this circuit. you can add as many loads to the circuit as long as you dont surpas the fuse's rating and the battery will just flow more current to sustain the 12 volts required. the icp circuit in the powerstroke works off a 5 volt v-ref, the pcm limited this circuit to 5 volts. i dont know the current rating but its irrelevant. it doesnt matter how much resistance you add or take away to it. its not a load bearing circuit, its a signal circuit. the source voltage\amperage will never change it is a fixed value. the pcm wants to see how much that fixed value changes when it makes its way back to the pcm. that value is infered as the oil pressure. no matter what method you use you need to drop the overall votlage that the pcm receives on the siganl circuit. to do that you need resistance. using a lower resistance the "old" way makes no sense to me. if you need a lower resistance then why are you adding resistors? the only theory i have is the way you install the 10k in the back of the connector allows 2 paths for the 5 volts to go, if you hae 10k in then the 5 volts trvels through the icp more and the 5.6k allows it to travel through the resistor more, since this method is in parralell not series it allows the 5 volts to take the easiest path back to the pcm so you can give the signal the oppertunity to bypass your mod thus ruining the purpose of it. as of right now this is a theory but it does follow the rules of basic electricity. i will do the volt probes and report on the findings but i do believe that i will find what i just stated above

 

I seen 37lb ft. increase on the dyno with my "old way" 10k mod, explain that perhaps.

Cowboy Steve

 

i never said it didnt work, i am saying you are not getting the full potential of it, i would almost put money down that if you took a stock truck then added the 10k the "old way", then the "c00nhunterjoe way" you would see more hp\torque running my way. how else can you explain to me that adding less resistance to a circuit causes more power, yet if that is so then why are you adding a resistor at all. please explain just that one question to me

 

Im not doubting your vast knowledge of circuits and resistance performance. I was just stating that if the new way is better then why did i se 37lb ft. on the dyno? I'll be the first to say that I lack the knowledge needed to understand the majority of the electrical systems in these trucks. So if there is merit to the "Coonhunter" way then lets do it on a stock truck and run it on the dyno and se whose works better.

Cowboy Steve

 

i would love to see both methods on a dyno, i do not have acces to one locally. i also do not doubt that the old version works, all i am saying is based on the laws of electricity and physics you are not getting your full potential, if you saw 37 ft lbs your way i would bet that i could get much more than that my way since i can get more oil pressure when adding a bigger resistor into the equation. plus my way doesnt allow the resisotr to be bypassed so more of the signal is manipulated, a side by side demo would be awesome, tomarrow i will do the mod both ways and see if i can feel a difference or not, i will also pull the chip out and try driving with the 22k in place as well. if the weather holds out i will try to get an in cab video and a tail pipe video showing my big difference in smoke levels and speed