Physics
The plane needs airflow over the wings to create lift. If the plane is not moving relative to the air around it, no lift can be generated. As I understand the problem, the plane is not moving relative to the air around it.
The conveyor is only acting on the wheels of the landing gear, not the body of the plane. Since the wheels can spin freely and are not given any limitations in the problem statement, the conveyor cannot stop the forward motion of the plane. The only thing the conveyor contributes is an APPARENT ground speed double that of normal takeoff speed.
The conveyor is only acting on the wheels of the landing gear, not the body of the plane. Since the wheels can spin freely and are not given any limitations in the problem statement,
the conveyor cannot stop the forward motion of the plane.
Thank you 76 supercab2,, this statement right here set me straight!
All the other smarts made my head hurt!
The conveyor is only acting on the wheels of the landing gear, not the body of the plane. Since the wheels can spin freely and are not given any limitations in the problem statement, the conveyor cannot stop the forward motion of the plane. The only thing the conveyor contributes is an APPARENT ground speed double that of normal takeoff speed.
*thinks some more*
I change my mind. The plane will fly.
If the plane is sitting on a conveyor and th conveyor is relying on the friction of the plane's wheels to turn the belt, then the plane will take off. If the belt is "self-powered" and is able to turn at the same rate of speed as the wheels, forward motion will be negated thus resulting in zero airflow over the wings and zero lift.
BTW, I have a very good friend who has over 15,000 hours in commericial jets (757, 767) and he says no way. Take it for what it's worth.
The plane needs airflow over the wings to create lift. If the plane is not moving relative to the air around it, no lift can be generated. As I understand the problem, the plane is not moving relative to the air around it.
I would love to see a video of the same setup on a treadmill. I don't expect the results would be any different.
It has to do with where the power is being applied to the plane. If the plane's power was being applied at the wheels, it would not fly. But it's not - the power is being applied to the chassis of the plane. The only way to negate the power is to apply an equal and opposite force to the chassis of the plane, making the net force on the plane zero. You can't apply that equal and opposite force on a plane through the wheels, because they move freely and independently.
Ford Trucks for Ford Truck Enthusiasts
But yeah, I already switched sides. The plane will fly.
If the plane is sitting on a conveyor and th conveyor is relying on the friction of the plane's wheels to turn the belt, then the plane will take off. If the belt is "self-powered" and is able to turn at the same rate of speed as the wheels, forward motion will be negated thus resulting in zero airflow over the wings and zero lift.
BTW, I have a very good friend who has over 15,000 hours in commericial jets (757, 767) and he says no way. Take it for what it's worth.
Think about it people, the thrust is going to propel the plane forward (doesn't matter what sort of plane)---which WILL create lift. It doesn't matter how fast the wheels are spinning---the wheels give the plane no motion.
The motion of the wheels is not what you would have to counteract to keep it from taking off---you would have to counteract the thrust of the engines.
The wheels are free rolling---their resistance makes no matter.
I thought a little diagram might help. The red arrows indicate the direction of travel for the belt. The green indicates the direction of travel for the wheels. The blue---indicates THRUST.
Belt is moving---say, 30 knots.
Take off requires 60 knots (by the way---don't get technical on me, I'm no pilot by any means---I don't have a clue as to just how fast 60 knots is... or how many 'knots' are required for take-off, but this is THEORY).
If the wheels are free-rolling (no brakes applied), they will roll with the conveyor belt, which, assuming the plane were somehow held from the top, the wheels would spin at 30 knots. Once the belt and wheels have reached their speed, kick on the thrust---which will have a magnitude of 60 knots. Here's the thing, assuming that the wheels are free-rolling, the wheels will not hold back the thrust what-so-ever. The motor (consequently the plane) will be moving at 60 knots.
Where does the extra 30 knots go???? To the wheels, they are spinning at 90 knots.
Plane moves 60 knots to the left, belt moves 30 to the right, and top of the wheels spin 90 knots (the bottom technically is 0 knots, but that's another argument) counter-clockwise (according to the picture).
If however, you were to lock the brakes up, and assuming there is perfect friction between the wheel and the road, given the same magnitudes, the plane will still move forward at 30 knots, but will drag the conveyor belt with it.
Anyways, chew on that for a little while. See what you thing---I think it's a fairly good example. Not to mention, I'm kinda proud of my picture.

To me, this is one of those "if you're driving in your car at night at the speed of light and turn your lights on, will your lights be effective???".
STan
STan
(BTW. The answer is, the lights can do whatever you want them to, because that car couldn't exist in our universe. So the laws of relativity don't apply.)







