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Ok- the only performance related mods I have are 3" dp to 4" exhaust, tymar intake, shimmed fpr, and 15.6k resistor.
Right now, if I hammer it, I can get a little black smoke which as we all know is unburnt fuel.
What I need someone to explain to me is how more black smoke equals more power.
It seems that if I am making black smoke now, I am burning some quantity of fuel in each cylinder and there is some left over. If I increase the amount of fuel to the cylinders, I will only be causing more fuel having not been burnt to exit the exhaust.
I understand that a chip will change engine parameters to better accomodate the burning of the extra fuel, but, other than installing injectors and a chip to handle them I don't see the advantage at this point of say, going to a 22k resistor just to make more waste smoke?
Am I understanding the theory of combustion and stoichiometric ratio properly?
More fuel= more boost. The added fuel will spin the turbo at faster speeds. True the black smoke is "wasted" fuel but it serves its purpose and creates higher pressures for more power. The newer model trucks are able to clean up smoke much better because of their vgt turbos which allows the motor to spool it up as if it were a small turbo but opens up when more flow is needed.
I know cOOn had done a lot with different resistors, I personally have not done them.
Stock tuning was programmed to make no smoke and meet certain emmisons.