When you click on links to various merchants on this site and make a purchase, this can result in this site earning a commission. Affiliate programs and affiliations include, but are not limited to, the eBay Partner Network.
I've got a 77 f-150 w/ 460 C6/ 3.00 9".
It has an Edelbrock performer manifold, 750 carb and double roller chain, CompCams 268H, lifters and valve springs, with Dynomax headers, 2 1/4" pipes with mustang flowmasters.
Anyway, My question is, what is the actual bore and stroke of the 460? The Chiltons and Haynes manuals are wrong because they only come up to about 422ci. They also say that the 460 has a shorter stroke that the 400ci.
Thanks, Jimmy
That only comes up to 421.66 CI.
The formula is Bore x Stroke x # of cyl. x 3.14 = CI
4.36 x 3.85 x 8 x 3.14 = 421.66 or 422
4.00 x 3.00 x 8 x 3.14 = 301.44 or 302
4.00 x 3.50 x 8 x 3.14 = 351.68 or 351
4.00 x 4.00 x 8 x 3.14 = 401.92 or 400
They are all close except for the 460. Those are the same dimensions that I had.
Jimmy
The formula mathematically is pi X radius squared X height X number of cylinders.
This equates to 3.14 X (half bore size)squared X stroke X 8.
You get the same number as the formula. It is a volume formula of a cylinder.
Mark
Rezvani's Latest Post-Apocalyptic Monster Is a Ford F-150 Raptor Underneath
Slideshow: Called the Fortress, the 850-horsepower pickup combines Raptor underpinnings with military-inspired features, survival equipment, and a starting price of $285,000.