Clarification on additional 1/0 ground cable
I understand the routing of the two 6-8awg FICM/firewall grounds, + to +, etc. My question is regarding the additional 1/0 ground cable. Does it go from the driver's side existing factory negative battery terminal to the engine block?
Much appreciated
Yes, but I'll expand.
What I was trying to do there was to lower and match the resistance between the two batteries on the negative side. Probably the best description to date (as I've learned more) is the flow from the passengers negative terminal to the engine block involves 1 bolted connection. With the factory setup for a single alternator, the driver's battery from the terminal goes through 3 bolted connections. So the resistance at each connection is summed.
An example for illustrative purposes would be if each bolted connection were a 2:
Passenger side a 2 value.
Drivers side a 2+2+2=6 value.
And why the driver's battery works less, it has higher flow resistance.
The most economical way and my original layout were to add a cable from the frame connection to the block, and instead of it being a 2=2=4 connection, it's more like 3 because the original path is now a parallel path. And it's inexpensive with only 1 short cable, a bolt, and a washer.
You can also run from the drivers negative terminal directly to the block, a little more costly due to the longer length, it may be easier than getting down on the frame. It's a 2 1/2.
Or if the terminal at the driver's negative battery is in poor shape and corroded, a replacement cable with a terminal end going directly to the block works and ignore the fame connection. That would be a 2.
Any of this is an improvement. But it's not like it's solving a major problem, but it's getting the batteries to work more equal.
There is a better way to do all of this, but it requires all new major cables and it's expensive, not something I'd do until the need to replace all the cables. I'll do that after I figure out how to get a 6.0L back together.
This is how parallel resistance is calculated regardless of resistance values or the number of resistances in parallel.
If you are describing resistances in parallel with three separate wires from the drivers battery to three separate grounds, the formula is 1/Rtotal = 1/R1+1/R2+1/R3. Using your numbers of 2,2,&2; then, 1/Rtotal = 1/2+1/2+1/2 or 1/Rtotal = .5+.5+.5. Rtotal = 1.5/1.
So, per your example,passenger side equals 2 and drivers side equals 1.5.










