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Old Jan 30, 2006 | 03:25 PM
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Question Brake Question

Do you heat up your rotors more by braking easy and early or hard and late?


I kind of lean toward the first " easy and early" would generate more heat.
 
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Old Jan 30, 2006 | 05:09 PM
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to slow the vehicle down from lets say 60 MPH takes a given amount of energy. if you stop fast, all the energy goes thru the brakes. if you stop slow, the vehicle will loose some of the energy thru rolling resistance and motor deceleration. take your foot off the gas at 60 mph and coast for 30 seconds---- if you dropped lets say 10 mph, that is energy that did not go into the brakes.
 
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Old Jan 30, 2006 | 05:33 PM
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Not to mention that the early/easy method will allow the brakes more time to disipate heat buildup.

Mike
 
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Old Jan 30, 2006 | 05:48 PM
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Steve, That wasn't the question. I personaly drive like I'm in a 18 wheeler, I start coasting way before I come to a red light. I can't even remember the last time I had to come to a complete stop at a light. The question is, which generates more heat, or rather which is harder on the rotors. I wish I had one of those laser type temp guns to check it.

Mike, or to build up heat.

Someone needs to check this out for us.
 
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Old Jan 30, 2006 | 08:58 PM
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If you were to graph it I'm guessing there would be a cross over were temp at the rotors is equal. No idea where that is, but in general the harder you apply the brakes the more friction is produced between the pads and the rotors and friction generates heat. On the flip side the longer the brakes are applied the more friction and heat will be generated. For what it's worth, I think longer braking is a better idea. The rotors will be able to dissapate the heat more easily and there will be less dramatic effects on the rotors. Heating and cooling the rotors rapidly will be more likely to cause them to warp given that they will expand and contract just as rapidly.
 
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Old Jan 31, 2006 | 07:44 AM
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If the brakes were doing ALL of the work in slowing the vehicle, there is no difference in the the heat generated by slow/easy vs. fast/hard. You are still converting the exact same amount of kinetic energy into thermal energy.

The dissipation of this waste heat, on the other hand is a different matter.

Over a slow/easy stop's time span, the heat will have a better chance to dissipate and will likely result in a lower peak rotor temperature than would a fast/hard stop.

Steve
 
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Old Jan 31, 2006 | 11:10 AM
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Originally Posted by projectSHO89
If the brakes were doing ALL of the work in slowing the vehicle, there is no difference in the the heat generated by slow/easy vs. fast/hard. You are still converting the exact same amount of kinetic energy into thermal energy.

The dissipation of this waste heat, on the other hand is a different matter.

Over a slow/easy stop's time span, the heat will have a better chance to dissipate and will likely result in a lower peak rotor temperature than would a fast/hard stop.

Steve
Not only would you have a lower peak, but you would also not have as sharp of a peak. The brake won't go from cold to hot really quick which is how things warp. It will gradually heat up to a lower peak because the energy is being released over a longer period of time and then get to cool from a lower peak to ambient as normal.

Basicly you don't have a sharp, rapid temperature swing.

Mike
 
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Old Jan 31, 2006 | 12:29 PM
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Rub your hands together real fast for a long period of time with light pressure. Now, push you hands together with force, and rub them together real fast.

That will give you an idea...
 
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Old Jan 31, 2006 | 06:21 PM
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Great Job ATC Crazy, you made this whole question a joke. A fifth grader probably could have come up with what you just said. Everyone is trying to get all scientific. LOL
 
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Old Jan 31, 2006 | 06:40 PM
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The Racers will tell you. It's the fast hard stops that generate all the heat.
 
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Old Feb 1, 2006 | 02:01 AM
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Smile More than you wanted to know

WORK = FORCE X DISTANCE = Force thru a Distance

Usually measured in Horse Power which is -
550 lbs per Ft Per Second or 33,000 Ft lbs per min

However In the question as stated:
Work = Work done on the rotor to slow it down which is converted to "BTU'S of Heat energy"

While it does not solve for a specified problem because many variables are not known such as inirtia, velocity, mass, surface area, heat transfer coefficients to name only a few;

The elementry application would indicated Fast & Hard i.e. (Max Force X (thru) distance ) would yeild Max Btu/Sec developing the greatest differential Temperature (Deta T) across the rotor or Maximum Temperature.

More useless trivia...
1 HP ~43 BTU's
1BTU Will increase 1 lb of water 1 Deg F
<TABLE cellSpacing=2 cellPadding=5 border=0><TBODY><TR><TD align=right>IF you really need to calculate it, (LOL) the formula below is a starter<TD><TR><TD><TD><TR><TD> <TD></TD></TR></TBODY></TABLE>

(Sorry, it's what 10 years of teaching in a vocational school will do to you)
 

Last edited by smecomark1; Feb 1, 2006 at 02:20 AM.
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Old Feb 1, 2006 | 08:09 AM
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LOL. and remember, bumble bee's can't fly either...
 
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Old Feb 1, 2006 | 10:34 AM
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Talking

Originally Posted by smecomark1
WORK = FORCE X DISTANCE = Force thru a Distance

IF you really need to calculate it, (LOL) the formula below is a starter<TD><TR><TD><TD><TR><TD> <TD></TD></TR></TBODY></TABLE>

(Sorry, it's what 10 years of teaching in a vocational school will do to you)
Secondmark, It would be wise for you to stay out of the kitchen and dont try to help your wife with her cooking!
She probably knows by now that it's better not to ask you any questions. She wont understand the answers anyway.
I saw some stone carvings on a cave wall once. They looked a lot like that formulae.
 
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Old Feb 1, 2006 | 10:36 PM
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Other benefits with "slow" braking would be the pads should last longer with less brake force, and fuel saving while the foot isn't applied to the gas pedal. As well as it's safer to drive that way, minimize the chance for collison if "fast" brake is applied, thus lowering the insurance premiums.
 
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