93 Bronco Door locks not working, switch or actuator? Please help
#1
93 Bronco Door locks not working, switch or actuator? Please help
So my door locks worked for like 2 days after I got the truck, I followed a door lock diagnosis manual I found on here and here is where I am stuck, i am checking the wiring and on the RH door locks I have P/BK, P/O and pink and yellowish color, the when I press lock I get power to the p/bk and p/o at the same time, I have checked this several times and when press unlock I get power to the P/O and P/BK at the same time and it says P/bk is lock and p/o is unlock, so is this faulty wiring or is the switch bad? I would assume you should not have lock and unlock powered at the same time correct?
#2
#3
I don't have a wiring diagram but I would guess that there is a poor connection linked to the ground. It is hard to explain here in the forum format but there are only 2 wires on the motor/actuator. Without any action selected, both of the motor wires will measure negative battery voltage with the other lead of the DVM connected to positive voltage. When an action is selected, one of the wires will be connected to positive voltage. The motor is the load in the circuit. If the other wire does not have a path to negative (ground) then the wire will measure positive until the open in the circuit. Measuring across the open in the circuit will show battery voltage, just like across the battery posts.
This image may help to explain this concept a little better.
http://www.autoshop101.com/trainmodu...cimage/vd1.gif
The light bulb is the load in this circuit and it has a 12v drop across it. If the switch was open, the bulb would have 0v drop and the switch would have a 12v drop across it.
Quote from http://www.autoshop101.com/trainmodu...s/circ118.html
VOLTAGE DROP
A voltage drop is the amount of voltage or electrical pressure that is used or given up as electrons pass through a resistance (load). All voltage will be used up in the circuit. The sum of the voltage drops will equal source voltage. A voltage drop measurement is done by measuring the voltage before entering the load and the voltage as it leaves the load. The difference between these two voltage readings is the voltage drop.
This image may help to explain this concept a little better.
http://www.autoshop101.com/trainmodu...cimage/vd1.gif
The light bulb is the load in this circuit and it has a 12v drop across it. If the switch was open, the bulb would have 0v drop and the switch would have a 12v drop across it.
Quote from http://www.autoshop101.com/trainmodu...s/circ118.html
VOLTAGE DROP
A voltage drop is the amount of voltage or electrical pressure that is used or given up as electrons pass through a resistance (load). All voltage will be used up in the circuit. The sum of the voltage drops will equal source voltage. A voltage drop measurement is done by measuring the voltage before entering the load and the voltage as it leaves the load. The difference between these two voltage readings is the voltage drop.
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