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Need quick reply please - How to get 185 ft-lbs with out a torque wrench?
I'm assembling the rear suspension and need to get 185 ft-lbs on a few nuts and bolts. I don't have a torque wrench and the closest NAPA only stocks up to 150.
I have a 750 CH impact gun. Is there one of the settings 1 thru 4 that'll approximate the 185 ft-lbs.
Proper size socket on a one foot breaker bar and have someone weighing 185 lbs. stand on the end of the breaker bar.
Somebody, knows about moment forces.
Pop quiz: Now how much torque would be exerted on the nut if that same 185lb person were to jump (fall) onto the 1' bar from 2 feet above the breaker bar?
Pop quiz: Now how much torque would be exerted on the nut if that same 185lb person were to jump (fall) onto the 1' bar from 2 feet above the breaker bar?
I figure the amount I save on labor justifys a couple tools here and there
I couldn't agree more. Doing your own work more than pays for some good tools!
Piolot: A lot of gear-heads have at least one torque wrench floating around, surely one of your friends/coworkers has one you could bum for a few minutes. Just a thought.
The money I saved doing this myself went towards a set of metric and sae deep impact sockets for the impact wrench, and will pay for an electrician to hook up the 6hp CH 60gal air compressor a relative gave us
The little pancake compressor earned its pay today I can tell you.
Pop quiz: Now how much torque would be exerted on the nut if that same 185lb person were to jump (fall) onto the 1' bar from 2 feet above the breaker bar?
Studying on the pop quiz. doesn't seem too hard to figure speed of the person falling for 2ft (I havent done that yet either) but how long does it take them to stop?
Studying on the pop quiz. doesn't seem too hard to figure speed of the person falling for 2ft (I havent done that yet either) but how long does it take them to stop?
Hint: Gravity's acceleration is 9.8m/s^2 or 32.2'/sec^2
Think of it this way instead: think of it as an instantaneous transfer of force, a dude is transferring 100% of his falling energy to the bar, so once that energy is transferred the dude is no longer part of the equation.
Does that help any?
Now in the real world you would never see 100% efficiency in the transfer of energy, the guys knees would bend and absorb some energy, and the bar would bend a little also absorbing some of the energy but that's really splitting hairs and incalculable requiring real world experimentation specific to the guy and the system as a whole. Theoretically though we can calculate this and get close enough.