need 550 hp
You're stuck on this hp # thing, why not see where you can take it without building the engine? There's quite a few around here that have done just that, Izzy who posted in your thread is at 450 and likes it just fine and is doing well on PMRs. You might find you like it just fine with bigger sticks, a turbo, some good live tuning and other supporting mods. Then if you don't like it or you break it, look in to taking it to the next level. Also I didn't catch if you answered what year your truck is, some years had PMR rods, some had forged which are said to be stronger.
You want what you want, good luck with it all. It's just most people come on here looking to see what they can do to get some more power and reliability out of thier trucks and then seem to get PMS and progress from there. Not too many start out wanting to take the leap to ludicrous speed right off the bat.
i was shooting for the 600 but after talking to swamps im now shooting for 550HP with my 38R and a set of 250cc to save about $5,000..parts are gathering for a winter build as we speak..
250/100 hybrids... $2200
Modded H2e or 38R/1.15... $2000-$2500
Studs... $450
Fuel system... $300-$600
GOOD tuning to control it... $400-$600
Ford Trucks for Ford Truck Enthusiasts
Each 1-hp of rejected heat energy is 42.4 Btu/min of waste heat and each 1-gal of coolant absorbs 8.3 Btu of heat energy for each 1*F of temperature increase ...so assuming a 20*F temperature difference between the top (supply) and the bottom (return) radiator hoses the gpm coolant flow through the radiator that's required to transfer 487 hp worth of "heat energy" into the ambient atmosphere is... {(487 hp)(42.4 Btu/min-hp)}/{(8.3 Btu/gal-*F)(20*F)}=125 gpm ...and this compares to a 52 gpm requirement for a stock 250 fwhp engine!
To maintain a 20*F temperature difference between the top and bottom radiator hoses for a 125 gpm coolant flow which is what's required to achieve a transfer of {(487 hp)(42.4 Btu/min-hp)}=20,649 Btu/min of waste heat into the ambient atmosphere requires a "very large" cfm airflow through the radiator's "heat exchanger" because each 1-lbm (pound mass) of air only absorbs 0.24 Btu of heat energy for each 1*F of temperature increase ...so assuming a 20*F temperature difference between the airflow entering and leaving the radiator's heat exchanger the mass airflow through the radiator's heat exchanger that's required to transfer 20,649 Btu/min of heat energy into the ambient atmosphere is... (20,649 Btu/min)/{(0.24 Btu/lbm-*F)(20*F)}=4,302 lbm/min ...and this compares to a 1,792 lbm/min requirement for a stock 250 fwhp engine!
At sea level the density of 80*F ambient air is 0.0735 lbm/ft^3 and this gives a required... (4,302 lbm/min)/(0.0735 lbm/ft^3)=58,530 ft^3/min ...or 58,530 cfm airflow through the radiator's heat exchanger and a 100*F day in Denver requires a 67,310 cfm airflow through the radiator's heat exchanger ...and this compares to a 24,380 cfm sea level requirement and a 28,045 cfm Denver requirement for a stock 250 fwhp engine!
Since 60 mph=5,280 ft/min each 1-ft^2 of radiator heat exchanger that's exposed to the airstream receives a 5,280 cfm RAM airflow so if there's 4 ft^2 exposed there's a 21,120 cfm RAM airflow at 60 mph and this RAM airflow alone is almost enough airflow to satisfy the 24,380 cfm sea level requirement of a stock 250 fwhp engine operating at full power ...but if you're towing up a 30 mph grade only a 2,640 cfm RAM airflow is received by each 1-ft^2 of exposed heat exchanger and this means there's only a 10,560 cfm RAM airflow to meet the 24,380 cfm sea level requirement of a stock 250 fwhp engine operating at full power ...and this means the radiator cooling fan needs to supply an additional 24,380-10,560=13,830 cfm FAN airflow to avoid overheating during a long slow climb near sea level and an additional 28,045-10,560=17,285 cfm FAN airflow to avoid overheating during a long slow climb near Denver!
For a 600 fwhp engine the radiator cooling fan needs to supply an additional 58,530-10,560=47,970 cfm FAN airflow to avoid overheating during a long slow climb near sea level and an additional 67,310-10,560=56,760 cfm FAN airflow to avoid overheating during a long slow climb near Denver!
So what kind of fans will provide about a 50,000 cfm FAN airflow? ...Hovercraft,Air Cushion Vehicle,Air Boat Propellers,Fans,Parts,Supplies, components and advice.
The above link shows a 32" fan with 9 blades that produces a 36,900 cfm airflow at a static pressure of 1" H20 and requires 33 hp at a 40 degree blade pitch and there's a 45" fan with 8 blades that produces a 77,500 cfm airflow at a static pressure of 1" H20 and requires 92 hp at a 40 degree blade pitch ...but considering that the airflow needs to be forced through the A/C condenser and the intercooler before even reaching the radiator I think a fan with a static pressure rating of more that 1" H20 is probably required ...and the above link also shows a 22" fan with 8 blades that produces a 16,200 cfm airflow at a static pressure of 4" H2O and at 3600 rpm requires 24 hp at a 50 degree blade pitch. I think this last 22" fan is comparable to the OEM fan but you'd need 3 of these fans to cool a 600 fwhp engine!
The bottom-line is that to actually use 600 fwhp you'd need a cooling system like the one below for a 600 fwhp C-15!
You can't safely get to 550 with 5k.
It takes alot more than that to get there..
I bet if you knew what 400 - 500 felt like you would be happy. The step from 500 plus starts taking alot more money.







