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Nov 15, 2009 | 04:03 PM

#16

69cj

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From: Middle Tn.

Quote:

Originally Posted by YoungMT Hick

ok so tapped into the driver's side amber side light for power and am using the existing ground near the back of the headlight. had to pull the headlight to get to those amber lights didnt know that. so i have power have a ground, drilled holes for the two led's, now going to solder the resistors to the positive side cover them in shrink wrap then connet them in parallel to the power and ground them in parallel, question i could only get 1K ohm resistors would it be better to run one resistor in series than running two resistors in parallel when i only need 496 ohm per led? or is that cutting it

No, resistors in series are additive. In parallel if resistance is the same for each resistor it is halved. If more than 2 resistors in parallel the formula is;

R1+R2+R3 divided by R1XR2XR3

Nov 15, 2009 | 04:07 PM

#17

YoungMT Hick

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From: Ballston Spa, NY

ok sorry still dont get it. so resistors in series add resistance??? so couldnt i just run one resistor for the two led's.

Nov 15, 2009 | 04:09 PM

#18

69cj

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From: Middle Tn.

Quote:

Originally Posted by YoungMT Hick

ok sorry still dont get it. so resistors in series add resistance??? so couldnt i just run one resistor for the two led's.

You would have to calculate twice the current. Current in parallel is additive.

Nov 15, 2009 | 04:19 PM

#19

YoungMT Hick

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From: Ballston Spa, NY

so like this (14.5-4.2[two led's])/.050 [current x2] = 206 ohm

Nov 15, 2009 | 04:28 PM

#20

69cj

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From: Middle Tn.

Quote:

Originally Posted by YoungMT Hick

so like this (14.5-4.2[two led's])/.050 [current x2] = 206 ohm

If the current for your ind. led's is .025 a each and the voltage rating of each led is 4.2 then yes.

Nov 15, 2009 | 04:35 PM

#21

ingman

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From: brigham city Utah

That's going to be really cool looking. Please make a right up on how you did it and post it so we all can use it. thanks.

Nov 15, 2009 | 04:52 PM

#22

YoungMT Hick

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From: Ballston Spa, NY

2.1vdc and 25 mV for each led

Nov 15, 2009 | 04:56 PM

#23

YoungMT Hick

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From: Ballston Spa, NY

do resistors have a direction of current flow pos neg

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Nov 15, 2009 | 04:58 PM

#24

69cj

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From: Middle Tn.

Quote:

Originally Posted by YoungMT Hick

do resistors have a direction of current flow pos neg

No, resistance is resistance.

Nov 15, 2009 | 05:00 PM

#25

YoungMT Hick

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From: Ballston Spa, NY

ok cool about to do the soldering soon

Nov 15, 2009 | 05:05 PM

#26

69cj

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From: Middle Tn.

Calcs. come to 248 ohms

Nov 15, 2009 | 05:29 PM

#27

YoungMT Hick

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From: Ballston Spa, NY

what voltage supply i used 14.5 i have a 1k ohm resistor i am planning on putting a resistor with each led

Nov 15, 2009 | 05:34 PM

#28

69cj

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From: Middle Tn.

Quote:

Originally Posted by YoungMT Hick

what voltage supply i used 14.5 i have a 1k ohm resistor i am planning on putting a resistor with each led

You keep changing the game plan. You last said you were going to use one resistor with 2 led's in parallel.

Nov 15, 2009 | 05:44 PM

#29

YoungMT Hick

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From: Ballston Spa, NY

ya i was but is that to much or can i do that thats what i am asking dont want to know numbers what do you think i should do just want the help sorry

Nov 15, 2009 | 05:56 PM

#30

69cj

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From: Middle Tn.

Quote:

Originally Posted by YoungMT Hick

ya i was but is that to much or can i do that thats what i am asking dont want to know numbers what do you think i should do just want the help sorry

Two parallel leds calls for 248 ohms. one led calls for 496 ohms.I think that one 1,000 with one led will work. If not you can always change the resistor but the calcs. would call for a 500 ohm. Main thing is resistors are cheaper than leds. Incidentally, if using two led's use a one watt resistor. Single led will be OK with a 1/2 watt resistor.

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