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An offshore well is located in the ocean at a point W, which is 5 miles from the closest shorepoint A on a straight shoreline. The oil is to be piped to a tank at Shorepoint B, that is 8 miles from A, by piping it on a straigh tline under water from W to some shorepoint P between A and B and hen on to B via a pipe along the shoreline. If the cost of laying pipe in $100,000 per mile under water and $75,000 per mile over land, where should the point P be located to minimize the cost of laying the pipe?
well its been a while but most places on the shoreline equal or exceed 950,000$, if there is a location that will be less than 950,000 it is between mile 7 to 8 ? For example at 7 miles away from point A on the shore its 8.7 miles aeay from W -cost is 945,000 at 7.5 miles away from A on the shore its 9.1 from W -cost is 947,000. Hope this helps.
This is a trick question for three reasons:
1. See the "Entitlement" thread in this section. Accordingly, any answer is correct.
2. Eco-***** have stifled any offshore oil drilling, so the problem lacks relevance.
3. Whether you're on land or sea, laying pipe can cost you a lot of money. So be careful
Six miles away from point A is where the pipeline should hit land, with two miles of onshore pipeline.
To do this you need two equations - one is the formula 100000X+75000Y which you want to minimixe. The other equation is the one for the right triangle with two variable sides. The one side is fixed at 5 miles and the other one ranges from 0 to 8 miles. So, your other equation is X=SQRT(5^2+(8-y)^2). Plug the equation above into the original equation, take the derivative and set it equal to zero and solve for X.
Or you could just do it in a spreadsheet and pick the smallest number like I did....
6 miles from point A would give you 8 miles of underwater pipe and 2 miles of shoreline pipe = 950,000 the dollar amount as if you went all underwater?
6 miles from point A would give you 8 miles of underwater pipe and 2 miles of shoreline pipe = 950,000 the dollar amount as if you went all underwater?
Not quite. 6 miles from A would be 7.81 miles underwater since it would be the hypotenuse of a right triangle with sides of 5 miles and 6 miles. This would be $781,000 of underwater pipe and $150,000 onshore pipe or $931,000 total.
Going straight from the well to the tank would be the hypotenuse of a right triangle with sides of 8 and 5 miles or 9.43 miles.
I have not checked Nitam's math, but his thought process is correct. you need to come up with asingle formula with 1 variable, take the derivative, set equel to zero, solve for x.
I have not checked Nitam's math, but his thought process is correct. you need to come up with asingle formula with 1 variable, take the derivative, set equel to zero, solve for x.
I had a fluid dynamics professor that never checked the math, just looked at how the problem was set up - the numerical answer wasn't important as long as you knew how to get there.
I wish the OP would chime in and let us know how we did.
I finally sat down and did the problem out and came up with the following solution:
Point P should be 5.7 miles from point A, resulting in 7.58 miles of underwater pipe and 2.3 miles of on land pipe. Total cost comes to $930,722.
But, that is only $18,000 less than running the pipe completely underwater. You'd spend that much and then some operating and maintaining the pump station.
Sorry for takin so long to get back, been busy, Nitramjr is correct along with Jimmy Dean. You had to take a triangle, get one variable, take the derivative and set to zero. Thanks to Nitramjr and Jimmy Dean for helpin out
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