Air consumption?
Thread Starter
|
Postmaster
Joined: Mar 2007
Posts: 2,612
Likes: 2
From: Dunwoody, GA
Originally Posted by Beerstalker
We need the approximate dimensions of the tank so we can figure out the surface area.
The Pacifier
Joined: Jan 2003
Posts: 8,245
Likes: 7
From: Cloverdale, BC
An air horn is an air horn. They'll work down to about 65 or 70 psi. But, the more air you got, the louder they are. The way a rig works is the compressor cuts out at 120 psi, cuts back in at 80 psi. Then there's a high pressure relief at 150 psi so the tank is safe. Horns are air hogs though, if you ever hear a truck laying on it's horns, it's for a good reason (getting cut off). Otherwise, they usually only "toot" them for backing up, or saying hello.
If I were to put money on your setup, I'd say you'd run out of air in about 7 seconds.
If I were to put money on your setup, I'd say you'd run out of air in about 7 seconds.
Thread Starter
|
Postmaster
Joined: Mar 2007
Posts: 2,612
Likes: 2
From: Dunwoody, GA
in my line of work we use them to clear the roads. 
our engines have air brakes so it's a lot larger systems. our rescue's w/o air brakes also have air horns, but i haven't checked what size tanks/compressors they have. i do know they last longer than 7 seconds.
our engines have air brakes so it's a lot larger systems. our rescue's w/o air brakes also have air horns, but i haven't checked what size tanks/compressors they have. i do know they last longer than 7 seconds.
Thread Starter
|
Postmaster
Joined: Mar 2007
Posts: 2,612
Likes: 2
From: Dunwoody, GA
So the volume of the 5gal tank is roughly .77 cu. ft.
The engineering problem:
What size tank will it take to run 2 horns operating at 7cfm & 110psi via a regulator with the initial tank pressure at 150psi for 15 seconds. Output pressure can not drop below 110psi.
The engineering problem:
What size tank will it take to run 2 horns operating at 7cfm & 110psi via a regulator with the initial tank pressure at 150psi for 15 seconds. Output pressure can not drop below 110psi.
Last edited by riggz; May 16, 2007 at 01:04 PM.
Thread Starter
|
Postmaster
Joined: Mar 2007
Posts: 2,612
Likes: 2
From: Dunwoody, GA
Here's what I've come up with using Boyle's law.
5gal tank = .77 cuft
.77 cuft tank @ 150psi = 8.6 cuft
.77 cuft tank @ 110psi = 6.5 cuft
8.6 cuft - 6.5 cuft = 2.1 cuft
7cfm x 2 = 14cfm = .233 cuft/sec
2.1 cuft / .233 cuft/sec = 9 seconds
8.5gal tank = 1.32 cuft
1.32 cuft tank @ 150psi = 14.8 cuft
1.32 cuft tank @ 110psi = 11.2 cuft
14.8 cuft - 11.2 cuft = 3.6 cuft
7cfm x 2 = 14cfm = .233 cuft/sec
3.6 cuft / .233 cuft/sec = 15.4 seconds
Any thoughts?
Code:
pa Va = pc Vc (1) where pa = atmospheric pressure (14.7 psi, 101.325 kPa) Va = volume of the gas at atmospheric pressure (cubic feet, cubic meter) pc = compressed pressure (psi, kPa) Vc = volume of the gas at compressed pressure (cubic feet, cubic meter)
.77 cuft tank @ 150psi = 8.6 cuft
.77 cuft tank @ 110psi = 6.5 cuft
8.6 cuft - 6.5 cuft = 2.1 cuft
7cfm x 2 = 14cfm = .233 cuft/sec
2.1 cuft / .233 cuft/sec = 9 seconds
8.5gal tank = 1.32 cuft
1.32 cuft tank @ 150psi = 14.8 cuft
1.32 cuft tank @ 110psi = 11.2 cuft
14.8 cuft - 11.2 cuft = 3.6 cuft
7cfm x 2 = 14cfm = .233 cuft/sec
3.6 cuft / .233 cuft/sec = 15.4 seconds
Any thoughts?
Last edited by riggz; May 16, 2007 at 01:11 PM.
Thread
Thread Starter
Forum
Replies
Last Post
marshallstanford
1999 - 2003 7.3L Power Stroke Diesel
12
Jul 15, 2016 06:42 AM
jdadamsjr
All Things Towing
8
Nov 26, 2014 04:17 PM
