Drilled rotors?
Why should one not use them?
Thanks
For example, lets say the rotor is solid and 1/4" thick. What would happen if a series of 1/8" holes were drilled?
For each hole drilled you would lose the surface area of a 1/8" circle on both sides. The area of a 1/8" circle is Pi times the radius squared. The radius is half the diameter: .125 / 2 = .0625". Square that and multiply times Pi: (.0625 * .0625) * 3.1415 = .012271... Finally, double it for both sides of the rotor and you have .024543 sq inches lost.
The hole will replace that with a surface area equal to the area of the wall of the hole. So the new area created is the circumference of the hole times the thickness of the rotor. Circumference is Pi times diameter: 3.1415 * .125" = .3926875. Then multiply times the thickness of the rotor: .3926875 * .375" = .1475258 sq inches gained.
That means that the hole actually has created 6 times more surface area than before. Using a 1/2" hole and everything else being the same, you create about 1.5 times the previous surface area.
Last edited by hank_48; Jun 30, 2006 at 04:13 PM.
For example, lets say the rotor is solid and 1/4" thick. What would happen if a series of 1/8" holes were drilled?
For each hole drilled you would lose the surface area of a 1/8" circle on both sides. The area of a 1/8" circle is Pi times the radius squared. The radius is half the diameter: .125 / 2 = .0625". Square that and multiply times Pi: (.0625 * .0625) * 3.1415 = .012271... Finally, double it for both sides of the rotor and you have .024543 sq inches lost.
The hole will replace that with a surface area equal to the area of the wall of the hole. So the new area created is the circumference of the hole times the thickness of the rotor. Circumference is Pi times diameter: 3.1415 * .125" = .3926875. Then multiply times the thickness of the rotor: .3926875 * .375" = .1475258 sq inches gained.
That means that the hole actually has created 6 times more surface area than before. Using a 1/2" hole and everything else being the same, you create about 1.5 times the previous surface area.

I've had mine on for 2 years now. I don't remember the name of the company I got them from (bought them in a group buy on another site). They are slotted and drilled, with zinc coating to prevent rust. I have had good luck with them so far. I actually wouldn't mind finding another set.
Let me see if I can get in touch with the guy I bought them from and get some info...
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$305.00
Thanks for the answers. I'm not sure I can spend that much for 2 rotors.
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They are $44 a piece for the plain brembo rotors. The plain brembos are supposed to be some of the best rotors available, and for the price they are a good deal.
They are $44 a piece for the plain brembo rotors. The plain brembos are supposed to be some of the best rotors available, and for the price they are a good deal.
Note: (Front) Drilled vented rotors. Not recommended for track use. Do not use with race compound brake pads. Drilled rotors are not warranted against warping or cracking.
Slotted and cross-drilled rotors are designed for performance applications. The slots and the cross-drilling is to vent gas built up from heat generated by extreme braking (allowing better pad to rotor contact). The vaned vents allow for better cooling for less fade.
If slotted and/or cross-drilled rotors are used then ceramic pads are recommended as others both deteriorate fast and can damage the rotors along with providing poor braking performance.
Also, to adequately obtain optimum braking performance, upgraded calipers and larger rotor diameters would be the proper path to follow.
I have the Baer Brake system (13" front/12" rear) slotted and cross-drilled on a 2000 turbocharged Mustang convertible. Appearance is great, but braking performance is even better.
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I am thinking of going with BaerClaw rotors and EBS pads, oem replacement size. Not sure what a complete system would cost, the Mustang was $3000 for both front and rear systems.
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