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Okay, let's take your first 3 digits...Let's say it's ABC. This number can be expressed as A-Hundreds plus B-tens plus C.
Okay, so this equals: 100A + 10B + C
When we multiple by 80 (Hmmm...I wonder where 80 came from, we'll see soon) we have: 8000A + 800B + 80C
Okay, Now we must add 1, so we have: 8000A + 800B + 80C + 1
Now we multiply by 250, so this leaves: 2000000A + 200000B + 20000C + 250
(You can now begin to see why 80 was chosen...nice round numbers that are 2 times multiples ot 10. Also, note the 250 term at the end.)
Okay, next we must add our last four digits. Let's say my last four digits are DEFG. This number is in the thousands and can be expressed as: 1000D + 100E + 10F +G
So, when we add it to what we were left with before, we have: (2000000A + 200000B + 20000C + 250) + (1000D + 100E + 10F +G)
We add it again and now have: (2000000A + 200000B + 20000C + 250) + (1000D + 100E + 10F +G) + (1000D + 100E + 10F +G)
This can be reduced to: (2000000A + 200000B + 20000C + 250) + 2(1000D + 100E + 10F +G)
When we multiply through by our by two: (2000000A + 200000B + 20000C + 250) + (2000D + 200E + 20F +2G)
(All the terms are now two times multiples of ten)
Anyway, now we subtract our 250(remember that) and the positive 250 term goes away: (2000000A + 200000B + 20000C) + (2000D + 200E + 20F +2G)
All that's left is to divide by 2(imagine that), so we are left with: (1000000A + 100000B + 10000C) + (1000D + 100E + 10F +G)
Voilla: Add the terms up and we have a number that looks like:
I would have been even more impressed if it would have come up with the phone number without asking for the last four digits. I new something was up when you had to enter all seven digits of your number in some part of the formula. I figured all the arithmetic was just a distraction to separate the seven digits you entered.
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