Another AIH delete question. Code eliminator question
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Cross-Country
Joined: Feb 2021
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Another AIH delete question. Code eliminator question
I fully understand what everyone does to eliminate the soft code when deleting the AIH. My question is what happens when the AIH is activated when using the 14gauge wire with 470ohm resistor in it?
Seems that the relay is large and would fry the little 14g wire that is grounded. And the little 470ohm resistor seems small as well and seems it would pop if the AIH was activated.
Any I out would be appreciated. I have read everywhere and have not seen the answer.
Yes I know the AIH almost never comes on but my point is can this little eliminator handle it when it does?
Thanks.
Seems that the relay is large and would fry the little 14g wire that is grounded. And the little 470ohm resistor seems small as well and seems it would pop if the AIH was activated.
Any I out would be appreciated. I have read everywhere and have not seen the answer.
Yes I know the AIH almost never comes on but my point is can this little eliminator handle it when it does?
Thanks.
Tuned
Joined: Jun 2003
Posts: 465
Likes: 53
From: Connecticut
I think you may have some misunderstanding of electricity.
V=IR. Or said differently, I=V/R (amps equals volts divided by resistance).
13.5V/470ohms = .03A (ck my math)
14g is good for some 15A? And a resistor won't flow any more than its rated current, which is controlled by the delta-V.
Throw 10KV at it and yeah you might have a problem. But not with 13.5V
V=IR. Or said differently, I=V/R (amps equals volts divided by resistance).
13.5V/470ohms = .03A (ck my math)
14g is good for some 15A? And a resistor won't flow any more than its rated current, which is controlled by the delta-V.
Throw 10KV at it and yeah you might have a problem. But not with 13.5V
Thread Starter
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Cross-Country
Joined: Feb 2021
Posts: 54
Likes: 2
Yes my ohms law understanding is weak at best. So what you are saying is the relay does not push AMPs, but pushes voltage. The grounded 14g wire w 470ohm resistor will not be damaged when the regulator activates.
I still dont complelety grasp it though. The original AIH wires seem to be 12 gauge or so (can anyone confirm this?) Part of my concern is this fact
I still dont complelety grasp it though. The original AIH wires seem to be 12 gauge or so (can anyone confirm this?) Part of my concern is this fact
I think you may have some misunderstanding of electricity.
V=IR. Or said differently, I=V/R (amps equals volts divided by resistance).
13.5V/470ohms = .03A (ck my math)
14g is good for some 15A? And a resistor won't flow any more than its rated current, which is controlled by the delta-V.
Throw 10KV at it and yeah you might have a problem. But not with 13.5V
V=IR. Or said differently, I=V/R (amps equals volts divided by resistance).
13.5V/470ohms = .03A (ck my math)
14g is good for some 15A? And a resistor won't flow any more than its rated current, which is controlled by the delta-V.
Throw 10KV at it and yeah you might have a problem. But not with 13.5V
Tuned
Joined: Jun 2003
Posts: 465
Likes: 53
From: Connecticut
I wouldn't say the relay PUSHES voltage, but OFFERS it. The resistor (any load) will only take as much amps as it is rated to pass, based on that delta-V.
I suppose you could think of it like water pressure in a hose, and the resistor as your thumb on the end; if your thumb is strong enough to stop the water pressure then the delta-pressure will not oversome your thumb's resistance. But if the water pressure is doubled (or more) then you may not be able to resist it.
The reason that the OE wire is larger is likely because the resistance of the AIH is less than 470 ohms, allowing higher amperage. - GA
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