Transcooler
The right way to do it is to run from the front of the trans to the radiator cooler, then to the 6.0L cooler, then to the rear of the trans.
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I believe Mark was just describing the proper fluid flow from the transmission, to the radiator cooler, through the trans cooler, and back to the transmission.
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Since the "water" in this case is engine coolant, the engine coolant is already at an elevated temperature, so engine coolant will be most effective in wicking away heat in the transmission fluid when the transmission fluid is significantly hotter than the engine coolant. The greater the disparity between transmission fluid temperature and engine coolant temperature, the more dramatic the effect the oil to water cooler will have at reducing the transmission fluid temperature during the brief pass through visit. If both fluids were at the same temperature, no heat transfer would take place. Equilibrium would already be close to parity.
There is only so much time that the transmission fluid has to dwell in oil to water cooler. The cooler is only a foot long, and the transmission fluid is (hopefully, at minimum) flowing at a rate of at least a gallon per minute. Not much time to take advantage of the thermal transfer efficiency of water immersion.
Even if it is 120 degrees F out side in the middle of August in Arizona, we know that this air will still be cooler than the 200 degree F engine coolant once the truck is at operating temperature. And, we also know that the 6.0L oil to air cooler, while much, much larger than the oil to water cooler, is still limited in it's ability to drop the temperature of it's temporary contents by the amount of time the transmission fluid remains resident in the cooler. Therefore, there is some limit as to how much the oil to air cooler can reduce the temperature. Call that limit x.
If the transmiission fluid enters the oil to air cooler after already having been somewhat cooled by the oil to water cooler, then the fluid enters at 1, is reduced by X, and the output yield temperature leaving the oil to air cooler will be y.
However, if the transmission fluid enters the oil to air cooler directly from the torque converter of the transmission, when the fluid is at it's absolute hottest, without benefit of any oil to water cooler pre cooling, then let's say the fluid enters the oil to air cooler at 2, is reduced by x, and the output yield temperature leaving the oil to air cooler will be z.
Without knowing the values of x, y, or z, we can clearly see that if x (the capacity of the 6.0L cooler to dissipate heat) is fixed, then output z will be greater than output y, because the entrance temperature 2 is greater than the entrance temperature of 1.
If I had a smoldering hot blob that was 300 degrees, and I had caldron of boiling water that was 200 degrees, and a room with a fan on that was 100 degrees, and I was allowed to use both the caldron and the fan to cool the hot blob, but only for a limited time with each method, and only in series one after the other, and I had to choose which cooling method to employ first... Then I would chose to first dip the 300 degree blob into the 200 degree caldron, so that the 300 degrees could cool down to 225 degrees before putting the blob in the 100 degree room with the fan.
That isn't the temperature of the coolant inside the radiator. The transmission cooler is in the tank that collects the coolant AFTER it passes through the radiator. So it's cooler than engine temperature. If it was still at engine temp in this tank you could just delete the radiator because it isn't doing anything.
It's like taking my 300 degree hot blob and dunking it into a 150 degree caldron of water, instead of a 200 degree caldron. The cooler water, and the greater initial temperature difference between my glob and the caldron water, enables more heat transfer.
Then I'd have a cooler glob to start with before putting it into a 100 degree room of air with a fan on for a minute. Since it can only stay in the room a minute, and since it has been established that air is a lot less efficient at transferring heat than water, I'm better off putting as cool of a glob as I can, to make the most of the efforts of the room and fan.
It's like taking my 300 degree hot blob and dunking it into a 150 degree caldron of water, instead of a 200 degree caldron. The cooler water, and the greater initial temperature difference between my glob and the caldron water, enables more heat transfer.
Then I'd have a cooler glob to start with before putting it into a 100 degree room of air with a fan on for a minute. Since it can only stay in the room a minute, and since it has been established that air is a lot less efficient at transferring heat than water, I'm better off putting as cool of a glob as I can, to make the most of the efforts of the room and fan.
That isn't the temperature of the coolant inside the radiator. The transmission cooler is in the tank that collects the coolant AFTER it passes through the radiator. So it's cooler than engine temperature. If it was still at engine temp in this tank you could just delete the radiator because it isn't doing anything.
I have mine plumbed through the 6.0 first and I’ll probably leave it that way. I’m running too cold as it is and I figure going through the radiator sencond might help keeping it from running even cooler. I usually see 125 empty, 150 loaded and worst case was pulling 12k in 100 degree weather at 175. I think a thermostat is in order.
















