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I have picked-out a 40x/12x/48x CD-RW drive for my old 'puter. Under system requirements, the drive calls for Pentium 166MHz and "Memory 128B Required".
What does the "B" in 128B mean? MegaByte or just plain Byte? This computer (PC-66, Pentium MMX 233MHz) currently has 64MB in SIMM and I will be adding a 128MB DIMM & 64MB DIMM modules for a total of 256MB which is supposedly the maximum memory size for the mainboard.
Sounds like just a typo--probably should be 128 MB--I cant recall any RAM with a B designation, especially for something as generic and platform wide as a CD drive
> This computer (PC-66, Pentium MMX 233MHz) currently has
>64MB in SIMM and I will be adding a 128MB DIMM & 64MB DIMM
>modules for a total of 256MB which is supposedly the maximum
>memory size for the mainboard.
>
>I should be OK, right?
When adding memory to a computer you can't mix the memory types. If you want to keep the 64mg of RAM and add memory then you can only add more 64mg sticks. If you have 3 memory slots then this will give you a total of 192mg. My understanding of this is that if you mix the memory types, your computer will only utilize the largest stick even though it will show the total RAM amount. So if you have one 128mg and two 64mg sticks, it will only use the 128mg. (And if your computer can handle 128mg sticks, then your motherboard's max. RAM capacity is 384mg; 128mgx3=384mg). If you know what kind of motherboard you have, or the model of the computer if it's a brand name, you can go to their websites and find the memory compatibilites. Otherwise you're buying memory that your computer won't use.
If I have any of this wrong, we have enough computer gurus here to straighten me out.
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