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Ok, here's the deal. I am in the finishing stages of a ZF S5-47 swap in my 1988 F250. I dont have the bracket that the center support or "carrier" bearing mounts to. I'm going to make my own, but I need to know how much the stock drop is. The truck is a 2wd regular cab long bed (133" WB) with a 7.3 diesel and a 10.25 rear. Any help would be greatly appreciated.
The bracket usually comes with the new bearing. From there you could use shims or
washers to get the "drop" you need. Does it have a lift? If so, this is a reason you would need to adjust the carrier bearing for less angle on the drive-shafts. Otherwise, no need to make some bracket that would adjust the bearing's location.
Thanks for the reply F100, but actually, there is a mount that the carrier attaches to. I'm not refering to the "U" shaped bracket that wraps around the rubber isolator. My truck was originally equipped with a C6 automatic, which uses a one piece driveshaft. I now have a ZF 5 speed in place of the C6. When I went to install the new two piece driveshaft, I found out that there is nowhere on the crossmember to mount the carrier bearing. In fact, it lines up with the "valley" in the middle of the crossmember. There is, however, four small holes where a bracket would attach. Ford had different size or "height" brackets depending on how the truck was equipped, ie: 4wd or 2wd, extended cab, regular cab, etc. I just need to know what the standard "drop" is for a stock suspension, 2WD, Reg. cab Longbed F250 with a ZF 5 speed tranny.
Something like this, of course, this is a 4wd truck, the one I need should be shorter.
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