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I have a 1996 standard cab long box, and I've been wondering about how the weight distribution between the two axles with a theoretical evenly distributed load in the bed.
Suppose you had 2000 pounds of wet sand exactly evenly distributed in the bed. While stationary, how much of this weight would the rear axle "see" compared to the front?
The rear axle would see almost all of the weight. I would say 95 percent.
I have the same truck with F-250 HD rear springs in it and when I put heavy loads like that in it, the back sags a ton compared to the front (no pun intended).
Weight behind the rear axle actually loads the rear axle with MORE than the load - removing weight from the front axle.
134" Wheelbase. 96" bed with ~ 36" behind the axle and 60" in front of the axle
So if your weight is dead-center in the bed, it's 22" from the rear axle and 112" from the front axle.
22 / 134 -> ~ 17% of the weight ends up on the front
112 / 134 -> ~ 83% of the weight ends up on the rear
Do you know what the dry weight of your truck is and the weight distribution ratio front to rear when unloaded? If the load is evenly distributed in the bed, you can treat the truck as an object with a center of gravity that you can then combine with the center of gravity of the load (somehow: these are my brother's words, not mine; he's going to school for physics).