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A friend and I are having an arguement about the engine displacement in the new 2000 F-150s and Superduty trucks. He says the 5.4L V-8 is a 350, but I think its at least a 400. Who is right? Also, what is the displacement of the 6.8L V-10 available on the superduty trucks? Thanks!!!
Sorry Luke ...youre both wrong . 5.4L is equal to 327 Cubic Inches . 6.8L is a 460 Cubic inch. Do the math . 5.0L = 302 , 5.8L = 351cu in . There is a formula for converting ...it escapes me at the momemt . I usually convert them based on the sizes I know .
The 5.4 is a 329.4 cubic inches.
It is reffered to as 330 though.
Here are some ford motors that are used in F150s:
4.2 is 257 V6 (97-current)
4.6 is 281 V8 (97-current )
5.4 is 330 V8 (97-current)
4.9 is 300 6cylinder (pre 97)
5.0 is 302 V8 (pre 97)
5.8 is 351 V8 (pre 97)
For chevorlet:
4.3 don't remember
5.0 is 305 pre 99
5.7 is 350 pre 99
4.8 don't remember 99-current
5.3 is 327 99-current
For dodge:
3.9 v6 (I think 239)
5.2 is 318 v8
5.9 is 360 v8
For 3/4 tons and 1 tons
Ford:
6.8 is V10 (I think 412) 99-current
7.5 is the 460 v8 pre 99
Chevorlet:
7.4 is 454 v8
6.0 v8 don't remember
Dodge:
8.0 V10 don't remember
As for calculating engine displacement, one liter (1000 cc) is roughly equivalent to 60 cubic inches. And although Ford has always advertised the 302 as a 5 liter, it is actually a 4.9 liter. They wanted it to "sound" larger than the old 4.9 liter straight-six. Other manufacturers have probably done this over the years, it's called marketing hype.