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the calculation is bore x bore x stroke x .7854 x number of cylinders. so, knowing that and knowing the bore is 4", the stroke is 3.98", and the # of cylinders is 6, you can do the math. for example:
.030= 304.6 cu. in. or 4.993L (you divide by 61 to convert CI to L
.060=309.15 cu. in. or 5.068L
.080=312.209 cu. in. or 5.118L
This would mean that the engines that are running around are bored to 312 in a 300 block are bored .080 over (not trying to step on toes here 78ihs2).
Hey can you guys tell a difference power wise with your 6s that are bored? Aren't you afraid of it screwing up the longgevity of the engine? The reason I ask is I've thought of having that done to mine. Where did you buy the parts?