crazy idea
Am I crazy (sure i am) but, can anyone give me some help?
Dyno's don't measure HP they measure torque. Then horsepower is calculated as a function of torque at a given RPM.
Like this:
torque x RPM
_________________ = HP
5252 (constant)
Which leads me to an old question. 2 engines are being tested. Engine1 turns 1000 rpm's and produces 1000 ft/lbs. of torque. Engine2 is turning 10,000 rpm's and is making 100 ft/lbs. of torque. Which engine produces more horsepower?
They're making exactly the same HP
Say the vehicle weighs 4000lb.
The transmission has a gear ratio of 3:1
The rear end ratio is 3:1
The tires are 32" tall (not factoring in tire deflection)
Hooking up a lead from the tach to the serial port of a laptop i can pick up the pulses of the coil, devide by the # of cyls and get a rudimentary tach.
Say i do a test run, from 1000rpm in second gear (3:1) to 4000rpm. From 0 seconds a program starts a log.
time - rpm - after gearing
0 sec - 1000rpm - 111.11rpm
.5 sec - 1100rpm - 122.22rpm
1 sec - 1200rpm - 133.33rpm
1.5 sec - 1300rpm - 144.44rpm
etc......to 4000rpm - 444.44rpm
for ever .5 second the engine is increasing 100rpm
and for every .5 sec the tires gain 11.11rpm
i'm stuck on how to put everything togeather.
[B]Hi-
Dyno's don't measure HP they measure torque. Then horsepower is calculated as a function of torque at a given RPM.
Like this:
torque x RPM
_________________ = HP
5252 (constant)
pbrstreetg, if it so than a 6.9 ltr Diesel must have approx. 226 hp.
330 x 3600
___________ = hp
5252
Could it be????
Jens



