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I followed the recent thread about removing the outside door handles from a 1940 with great interest. It would appear that the same process, holding the inside handle fully open and wiggling out the outside handle applies to my 1947 one ton as there is no access for a set screw as in 1948 and newer. Can anyone confirm this is so ? Thanks,
All that holds the handle are the two screws on the outside body. The handle has a square shaft, (which tends to rust). At the end of the shaft, about 3/8"-1/2" back, the square is rounded off for about 3/8". The shaft goes into the lock housing (matches square, but ends up at the rounded portion) and into the interior mechanism. The square part at the end moves the mechanism and the round portion just runs through the housing. When you remove the square of the end inside must line up with the square of the housing. That is why the door handle needs held in the open position (or there-abouts) so the interior square and housing square align. My explanation is confusing as hell. Use lots of WD40. I'll send a pict of the shaft end if you need it.
Your description actually makes good sense to me. I am soaking the shaft in penetrating oil for now but I can much better visualize what needs to happen.
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