I am working on my explorer again. Its a 4x4. Replaced rotors, calipers, and pads. The one problem I have always had is getting the correct torque spec for the front wheel bearing lock nut. I know back in the old days you would torque the wheel bearing down to set the bearings, thing then back the nut off a bit and stick in a cotter pin. I have even looked in manuals and the torque procedure was always vague. If someone could clear this up it would be a great help !
1997 Ford F-150 SC 4x4 5.4 XLT Silver full power
1990 Ford F-250 SC 460 E4OD XLT Lariat 2-tone Brown power windows, locks etc.
1992 Ford Explorer XLT white 4x4 four door. Loaded.
Same basic procedure, only instead of a cotter pin, there's a locking key (auto hub) or locking ring (manual hub). If you want to put numbers to it, haynes/Chiltons specify 30-40 ft lbs for seating the bearings, and about 16 inch lbs for the final torque.
'87 Bronco II XLT 4x4 & '92 Explorer XLT 4x4 & '98 Chev Suburban K1500 SLT 4x4
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