Differential Equations help?
#1
Differential Equations help?
I'm having some trouble figuring this problem out and was looking for some help..
I have to solve y'+2xy=0 using a series solution.
So far I have [sum of nCnX^n from n=0 to infinity] + 2 [sum of CnX^(n+1) from n=0 to infinity] = 0
and I don't know where to go from here any ideas?
I have to solve y'+2xy=0 using a series solution.
So far I have [sum of nCnX^n from n=0 to infinity] + 2 [sum of CnX^(n+1) from n=0 to infinity] = 0
and I don't know where to go from here any ideas?
#3
If you still have time, bust out in tears and run, screaming, to your TA. Nobody without a math degree can help you now. And pray that your professor uses a wicked curve, cause that's the only hope you have of passing the class.
Ok, little bit of sarcasm in there, but seriously-DE is just short of impossible, and your professor or TA are going to be your best bet. This is a class that 95% of people who take it either hate it or have no idea what's going on (I did both) and you can't afford to wait until the last minute for anything. Try to read the notes beforehand and if you don't understand the lectures then go to office hours and ask questions.
To answer your question, no I have no idea. You got farther than I would have.
Ok, little bit of sarcasm in there, but seriously-DE is just short of impossible, and your professor or TA are going to be your best bet. This is a class that 95% of people who take it either hate it or have no idea what's going on (I did both) and you can't afford to wait until the last minute for anything. Try to read the notes beforehand and if you don't understand the lectures then go to office hours and ask questions.
To answer your question, no I have no idea. You got farther than I would have.
#4
I can't help you, and I took the class twice. What I do know, is that this is a first-order problem. Looking in my old Differential Equations book, it mentions that you will need to use the "recurrence formula". Just remember, Google and other search engines are your best friends when it comes to some of this stuff. There are some colleges and universities that have some really good online notes, and examples. What I learned in this class, I used very little after I took it. Some of it I saw again in circuits, fluid mechanics, and environmental engineering classes.
#5
Originally Posted by captain p4
I'm having some trouble figuring this problem out and was looking for some help..
I have to solve y'+2xy=0 using a series solution.
So far I have [sum of nCnX^n from n=0 to infinity] + 2 [sum of CnX^(n+1) from n=0 to infinity] = 0
and I don't know where to go from here any ideas?
I have to solve y'+2xy=0 using a series solution.
So far I have [sum of nCnX^n from n=0 to infinity] + 2 [sum of CnX^(n+1) from n=0 to infinity] = 0
and I don't know where to go from here any ideas?
what is the ' is that y squared?
if so, wouldn't y=0 and x= +/- 1
how you get to that solution I couldn't tell ya.
#6
#7
Do they give you some initial conditions? You might try this link.
http://www.sosmath.com/diffeq/diffeq.html
http://www.sosmath.com/diffeq/diffeq.html
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#12
bczolone you are one smart dude! Since my retirement, I've been revisiting calc, a little at a time, just to make my brain hurt. Maybe I'll get caught up enough to appreciate your analysis
Anyway, when I took diff many years ago, the prof was a really great guy. He was a math junkie, with the little office, and no outside interests, but he was still a great guy.
He was kind enough to tell us that there was no real reason to ever solve diff eqs. He also said that the math world concentrated on classifying the various equations as sovable or not.
One night, he proved his point. He handed out a sample equation, which he maintained was too hard for even the Russians to solve. ( As if I'd know). Then he showed how a relatively simple computer algorithm could approximate a solution good enough for any reasonable use.
I took this to mean study hard, pass the class, and don't worry about it.
I did, and never looked back.
ford2go
Anyway, when I took diff many years ago, the prof was a really great guy. He was a math junkie, with the little office, and no outside interests, but he was still a great guy.
He was kind enough to tell us that there was no real reason to ever solve diff eqs. He also said that the math world concentrated on classifying the various equations as sovable or not.
One night, he proved his point. He handed out a sample equation, which he maintained was too hard for even the Russians to solve. ( As if I'd know). Then he showed how a relatively simple computer algorithm could approximate a solution good enough for any reasonable use.
I took this to mean study hard, pass the class, and don't worry about it.
I did, and never looked back.
ford2go
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#14
Okay, what the hell are you guys talking about? None of what I just read made ANY sense at all. A math problem classified as unsolveable? Hmm. Maybe there is such thing as global warming...
Kidding. I have no desire to study DE or Calculus. Not my thing. But don't think I'm taking away from what you guys are doing. More power to ya.
Kidding. I have no desire to study DE or Calculus. Not my thing. But don't think I'm taking away from what you guys are doing. More power to ya.
#15